Capacitors continued

The voltage across the capacitors in the last example was obvious! ie 12 volts. In complex circuits
it is not quite so simple.So,yes you've guessed it,one more formula.
Q =VC were "Q"= the charge in coulombs(a bit like current). V = voltage
and C = the value of the capacitor in Farads.
So lets look at the first example again

If we wanted to know the voltage across C1 and the applied voltage was say 12 volts,so first we
need total capacitance ie. 4 mF,then we require the "current" so Q =VC = 12 x 4 x 10 ^-6
= 48 x 10 ^{- 6}, leave it like that for now. V = Q/C there for 48 x 10 ^-6 divided by
12 x 10 ^-6 = 4 volts,and as all the capacitors have the same value then the total voltage will
equal the applied voltage.Good Eh! Try a little test? OK click next.

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